1/16x^2-1/8x=1

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Solution for 1/16x^2-1/8x=1 equation: 


x in (-oo:+oo)

(1/16)*x^2-((1/8)*x) = 1 // - 1

(1/16)*x^2-((1/8)*x)-1 = 0

(1/16)*x^2+(-1/8)*x-1 = 0

1/16*x^2-1/8*x-1 = 0

DELTA = (-1/8)^2-(-1*1/16*4)

DELTA = 17/64

DELTA > 0

x = ((17/64)^(1/2)+1/8)/(1/16*2) or x = (1/8-(17/64)^(1/2))/(1/16*2)

x = 8*((17/64)^(1/2)+1/8) or x = 8*(1/8-(17/64)^(1/2))

x in { 8*(1/8-(17/64)^(1/2)), 8*((17/64)^(1/2)+1/8) }

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